STATEMENT -1 : An object is placed inside a liquid and screen through air perpendicularly look at shorter depth than its actual depth.
and
STATEMENT - 2 : When light passes from denser medium to rarer medium it deviates away from normal.

Options

A. a.Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. b.Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. c.Statement-1 is True, Statement-2 is false
D. d.Statement-1 is False, Statement-2 is True

Answer

To solve the problem, we will analyze both statements provided in the question step by step.

### Step 1: Analyze Statement 1
**Statement 1:** An object is placed inside a liquid and viewed through air perpendicularly appears to be at a shorter depth than its actual depth.

- When an object is submerged in a liquid and viewed from above (through air), the light rays coming from the object undergo refraction at the interface between the liquid and air.
- According to the laws of refraction, when light travels from a denser medium (liquid) to a rarer medium (air), it bends away from the normal.
- This bending of light causes the object to appear at a position that is shallower than its actual position. Therefore, the apparent depth is less than the actual depth.

**Conclusion for Statement 1:** This statement is true.

### Step 2: Analyze Statement 2
**Statement 2:** When light passes from a denser medium to a rarer medium, it deviates away from the normal.

- Again, we consider the transition of light from a denser medium (like water) to a rarer medium (like air).
- According to Snell's Law, the relationship between the angles of incidence and refraction is given by:

\[ \mu_1 \sin(i) = \mu_2 \sin(r) \]

where \( \mu_1 \) is the refractive index of the denser medium, \( \mu_2 \) is the refractive index of the rarer medium, \( i \) is the angle of incidence, and \( r \) is the angle of refraction.

- Since the refractive index of the rarer medium is less than that of the denser medium (\( \mu_2 < \mu_1 \)), it follows that:

\[ \frac{\sin(i)}{\sin(r)} = \frac{\mu_1}{\mu_2} \]

- This implies that \( \sin(r) > \sin(i) \), leading to the conclusion that the angle of refraction \( r \) is greater than the angle of incidence \( i \). Thus, the light ray bends away from the normal.

**Conclusion for Statement 2:** This statement is also true.

### Final Conclusion
Both statements are true, and Statement 2 provides a correct explanation for Statement 1. Therefore, the correct option is A: Both statements are true, and Statement 2 is the correct explanation of Statement 1.

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