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If the speed of photoelectrons is 10^(4...

If the speed of photoelectrons is ` 10^(4) m//s ` , what shold be the frequency of the incident radiation on a potassium metal? Given : Work function of potasslum = 2.3 eV .

Text Solution

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`E=K_"max"+phi`
`=1/2mv^2+phi`
`=1/2xx9xx10^(-31)xx(10^4)^2+2.3xx1.6xx10^(-19)`
`=4.5xx10^(-23) J + 3.68 xx 10^(-19)`
`=3.68xx10^(-19)` J
`v=E/h=(3.68xx10^(-19))/(6.63xx10^(-34))` Hz
`=0.56xx10^15` Hz
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