Home
Class 12
PHYSICS
If de Broglie wavelength of an electron ...

If de Broglie wavelength of an electron is 0.5467 Å,
find the kinetic energy of electron in eV. Given `h=6.6xx10^(-34)` Js ,
e=`1.6xx10^(-19)` C, `m_e=9.11xx10^(-31)` kg.

Text Solution

Verified by Experts

`E_k=1/2h^2/(mlambda^2)=1/2xx((6.6xx10^(-34))^2)/(9.11xx10^(-31)xx(0.5467xx10^(-10))^2)J`
`E_k` in eV =`1/2xx((6.6xx10^(-34))^2)/((9.11xx10^(-31))xx(1.6xx10^(-19))xx(0.5467xx10^(-10))^2)`=500 eV
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE OF RADIATION AND MATTER

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|41 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION A. Objective (Only one answer)|50 Videos

  • CURRENT ELECTRICITY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-J|10 Videos

  • ELECTRIC CHARGES AND FIELDS

    AAKASH INSTITUTE ENGLISH|Exercise comprehension|3 Videos

Similar Questions

Explore conceptually related problems

What is the (a) momentum (b) speed and (c) de-Broglie wavelength of an electron with kinetic energy of 120 eV. Given h=6.6xx10^(-34)Js, m_(e)=9xx10^(-31)kg , 1eV=1.6xx10^(-19)J .

The de Broglie wavelength of an electron with kinetic energy 120 e V is ("Given h"=6.63xx10^(-34)Js,m_(e)=9xx10^(-31)kg,1e V=1.6xx10^(-19)J)

Calculate de - Broglie wavelength of an electron having kinetic energy 2.8xx10^(-23)J

Calculate the (a) momentum and (b) de-Broglie wavelength of the electrons accelerated through a potential difference of 56V. Given, h=6.63xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg, e=1.6xx10^(-19)C .

Light of wavelength 4000Å is incident on barium. Photoelectrons emitted describe a circle of radius 50 cm by a magnetic field of flux density 5.26xx10^-6 tesla . What is the work function of barium in eV? Given h=6.6xx10^(-34)Js , e=1.6xx10^(-19)C, m_e=9.1xx10^(-31)kg.

Calculate de Broglie wavelenth of a neutron (mass, m=1.6xx10^(-27) kg) moving with kinetic energy of 0.04 eV.

Find de-Broglie wavelength of electron with KE =9.6xx10^(-19)J .

What is the strength of transverse magnetic field required to bend all the photoelectrons within a circle of a radius 50 cm when light of wavelength 3800 Å is incident on a barium emitter ? (Given that work function of barium is 2.5 eV, h=6.63xx10^(-34)js, e=1.6xx10^(19)C,m=9.1xx10^(-31)kg

Find the momentum of an electron having wavelength 2A^(0)(h=6.62 xx 10^(-34)Js)

If an electron has an energy such that its de Broglie wavelength is 5500 Å , then the energy value of that electron is (h= 6.6 xx 10^(-34)) Js, m_( c) = 9.1 xx 10^(-31) kg