For intensity l of a light of waelength ...

For intensity l of a light of waelength ` 5000 Å ` the photoelectron saturation current is` 0.40 mu Å` and stopping potential is 1.36 V . Find the work fucntion of metal .

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The correct Answer is:

1.1 eV

`E=w_0=K_"max", E="hc"/lambda`

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