An isolated hydrogen atom emits a photon of `10.2 eV`.
(i) Determine the momentum of photon emitted (ii) Calculate the recoil momentum of the atom
(iii) Find the kinetic energy of the recoil atom [Mass of proton `= m_(p) = 1.67 xx 10^(-27) kg`]

Explanation

To solve the problem step by step, we will address each part of the question systematically.

### Given Data:
- Energy of the emitted photon, \( E = 10.2 \, \text{eV} \)
- Mass of the hydrogen atom (proton), \( m_p = 1.67 \times 10^{-27} \, \text{kg} \)
- Speed of light, \( c = 3 \times 10^8 \, \text{m/s} \)
- Conversion factor: \( 1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J} \)

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