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In Rutherford's alpha-rays scattering ex...

In Rutherford's alpha-rays scattering experiment, the alpha particles are detected using a screen coated with

A

Copper sulphide

B

Zinc sulphide

C

Graphite

D

Gold

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The correct Answer is:
To solve the question regarding the detection of alpha particles in Rutherford's alpha-ray scattering experiment, we will follow these steps: ### Step-by-Step Solution: 1. **Understanding the Experiment**: Rutherford's alpha-ray scattering experiment was designed to probe the structure of the atom by observing how alpha particles interact with a thin foil of gold. 2. **Detection Method**: In this experiment, alpha particles are emitted and directed towards a target. To detect these particles after they interact with the target, a detection screen is required. 3. **Material Used for Detection**: The screen used for detecting alpha particles is crucial. It needs to be sensitive enough to register the impact of the alpha particles. 4. **Identifying the Coating**: The correct material that was used to coat the detection screen in Rutherford's experiment is zinc sulfide (ZnS). When alpha particles strike the zinc sulfide screen, they produce flashes of light (scintillations). 5. **Conclusion**: Based on the information about the detection method and the materials used, we conclude that the screen is coated with zinc sulfide. ### Final Answer: The alpha particles are detected using a screen coated with **zinc sulfide**. ---
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Rutherford's alpha-scattering experiment

In scattering experiment , alpha -particles were deflected by

alpha -Particles can be detected using

Rutherford's alpha-particle scattering experiment discovered

Assertion : In Rutherford's alpha -particle scattering experiment, most of the alpha -particles were deflected by nearly 180^(@) . Reason : The positive charge of the atom is spread throughout the atom that repelled and deflected the positively charged alpha -particles.

Alpha rays are

Rutherford model: The approximate size of the nucleus can be calculated by using energy conservation theorem in Rutherford's alpha -scattering experiment. If an alpha -particle is projected from infinity with speed v towards the nucleus having Z protons, then the alpha -particle which is reflected back or which is deflected by 180^@ must have approached closest to the nucleus .It can be approximated that alpha particle collides with the nucleus and gets back. Now if we apply the energy conservation equation at initial point and collision point then: (P.E.)_i= 0 , since P.E. of two charge system separated by infinite distance is zero. Finally the particle stops and then starts coming back. 1/2m_alpha v_alpha^2+0=0+(Kq_1q_2)/Rimplies 1/2m_alphav_alpha^2=K(2exxZe)/R implies R=(4KZe^2)/(m_alphav_alpha^2) Thus the radius of nucleus can be calculated using above equation. The nucleus is so small a particle that we can't define a sharp boundary for it Radius of a particular nucleus is calculated by the projection of alpha -particle from infinity at a particular speed. Let this radius is the true radius . If the radius calculation for the same nucleus is made by another alpha -particle with half of the earlier speed, then the percentage error involved in the radius calculation is :

Rutherford model: The approximate size of the nucleus can be calculated by using energy conservation theorem in Rutherford's alpha -scattering experiment. If an alpha -particle is projected from infinity with speed v towards the nucleus having Z protons, then the alpha -particle which is reflected back or which is deflected by 180^@ must have approached closest to the nucleus .It can be approximated that alpha particle collides with the nucleus and gets back. Now if we apply the energy conservation equation at initial point and collision point then: (P.E.)_i= 0 , since P.E. of two charge system separated by infinite distance is zero. Finally the particle stops and then starts coming back. 1/2m_alpha v_alpha^2+0=0+(Kq_1q_2)/Rimplies 1/2m_alphav_alpha^2=K(2exxZe)/R implies R=(4KZe^2)/(m_alphav_alpha^2) Thus the radius of nucleus can be calculated using above equation. The nucleus is so small a particle that we can't define a sharp boundary for it An alpha -particle with initial speed v_0 is projected from infinity and it approaches up to r_0 distance from a nuclie. Then, the initial speed of alpha -particle, which approaches upto 2r_0 distance from the nucleus is :

Rutherford's alpha- scattering experiment was successful in discovering

Rutherford's alpha particle scattering experiment eventually led to the conclusion that

AAKASH INSTITUTE ENGLISH-ATOMS-ASSIGNMENT SECTION A Objective (One option is correct )
  1. Thickness of the foil of gold used in alpha-particle scattering experi...

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  2. In Rutherford's alpha-rays scattering experiment, the alpha particles ...

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  3. In Rutherford's experiment , scattering of more than 1^@ was observed ...

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  4. In scattering experiment , alpha -particles were deflected by

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  5. Energy of the beam of alpha-particles used by Geiger and Marsden in sc...

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  6. Source of alpha-particles used in scattering experiment was

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  7. What is the distance of closest approach to the nucleus for an alpha-p...

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  8. An alpha-particle colliding with one of the electrons in a gold atom l...

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  9. The angular momentum of an electron in a hydrogen atom is proportional...

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  10. When an electron in hydrogen atom is taken from fourth excited state t...

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  11. What is the angular momentum of an electron in Bohr's hydrogen atom wh...

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  12. The ground state energy of H-atom is 13.6 eV. The energy needed to ion...

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  13. The energies of three conservative energy levels L3,L2 and L1 of hydro...

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  14. The product of angular speed and tangential speed of electron in n^"th...

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  15. The speed of an electron in the 4^"th" orbit of hydrogen atom is

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  16. What should be the ratio of minimum to maximum wavelength of radiation...

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  17. The ratio of energies of hydrogen atom in its first excited state to t...

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  18. How many spectral lines are emitted by atomic hydrogen excited to the ...

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  19. The energy of hydrogen atom in its ground state is -13.6 eV , the ener...

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  20. In which transition of a hydrogen atom, photons of lowest frequency ar...

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