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The product of angular speed and tangent...

The product of angular speed and tangential speed of electron in `n^"th"` orbit of hydrogen atom is

A

Directly proportional to `n^2`

B

Directly proportional to `n^3`

C

Inversely proportional to `n^4`

D

independent of n

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The correct Answer is:
To find the product of angular speed and tangential speed of an electron in the nth orbit of a hydrogen atom, we can follow these steps: ### Step 1: Understand the Definitions - **Tangential Speed (V)**: The speed of an electron moving along its circular orbit. It can be expressed as: \[ V = \frac{2 \pi r}{T} \] where \( r \) is the radius of the orbit and \( T \) is the time period of the electron's orbit. - **Angular Speed (ω)**: The rate of change of angular displacement, given by: \[ \omega = \frac{2 \pi}{T} \] ### Step 2: Relate Tangential Speed and Angular Speed - The relationship between tangential speed and angular speed is given by: \[ V = r \cdot \omega \] ### Step 3: Express Tangential Speed for Hydrogen Atom For the hydrogen atom, the tangential speed \( V \) of the electron in the nth orbit can be expressed as: \[ V = 2.18 \times 10^6 \frac{Z}{n} \] where \( Z \) is the atomic number (for hydrogen, \( Z = 1 \)). ### Step 4: Express Angular Speed for Hydrogen Atom The angular speed \( \omega \) can be expressed as: \[ \omega = \frac{2 \pi}{T} \] From the Bohr model, we know that the time period \( T \) is proportional to \( n^3 \): \[ T \propto n^3 \implies \omega \propto \frac{1}{n^3} \] ### Step 5: Calculate the Product Now, we need to find the product \( V \cdot \omega \): \[ V \cdot \omega = \left(2.18 \times 10^6 \frac{Z}{n}\right) \cdot \left(\frac{2 \pi}{T}\right) \] Substituting \( \omega \): \[ V \cdot \omega \propto \frac{1}{n} \cdot \frac{1}{n^3} = \frac{1}{n^4} \] ### Conclusion Thus, the product of angular speed and tangential speed of the electron in the nth orbit of a hydrogen atom is inversely proportional to \( n^4 \). ### Final Answer The product of angular speed and tangential speed of the electron in the nth orbit of a hydrogen atom is: \[ \frac{1}{n^4} \] ---
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AAKASH INSTITUTE ENGLISH-ATOMS-ASSIGNMENT SECTION A Objective (One option is correct )
  1. The ground state energy of H-atom is 13.6 eV. The energy needed to ion...

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  2. The energies of three conservative energy levels L3,L2 and L1 of hydro...

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  3. The product of angular speed and tangential speed of electron in n^"th...

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  4. The speed of an electron in the 4^"th" orbit of hydrogen atom is

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  5. What should be the ratio of minimum to maximum wavelength of radiation...

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  6. The ratio of energies of hydrogen atom in its first excited state to t...

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  7. How many spectral lines are emitted by atomic hydrogen excited to the ...

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  8. The energy of hydrogen atom in its ground state is -13.6 eV , the ener...

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  9. In which transition of a hydrogen atom, photons of lowest frequency ar...

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  10. Total energy of an electron in the hydrogen atom in the ground state i...

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  11. Using Bohr's formula for energy quantization, the ionisation potenti...

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  12. Which of the following cannot be the value of ionisation energy for a ...

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  13. Name the spectral series of hydrogen atom, which be in infrared region...

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  14. The energies of three conservative energy levels L3,L2 and L1 of hydro...

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  15. if the wavelength of first member of Lyman series is lambda then calcu...

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  16. In Bohr's model of the hydrogen atom, the ratio between the period of ...

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  17. How many time does the electron go round the first bohr orbit of hydro...

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  18. If an electron in hydrogen atom jumps from third orbit to second orbit...

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  19. If radius of first orbit of hydrogen atom is 5.29 ** 10^(-11) m, the r...

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  20. Bohr's atomic model is applicable for

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