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The lines in Balmer series have their wa...

The lines in Balmer series have their wavelengths lying between

A

1266 Å to 3647 Å

B

642 Å to 3000 Å

C

3647 Å to 6563 Å

D

Zero to infinity

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To find the range of wavelengths in the Balmer series, we will follow these steps: ### Step-by-Step Solution: 1. **Understanding the Balmer Series**: The Balmer series corresponds to the transitions of electrons in a hydrogen atom from higher energy levels (n ≥ 3) to the second energy level (n = 2). 2. **Using the Rydberg Formula**: The wavelength of the emitted light during these transitions can be calculated using the Rydberg formula: \[ \frac{1}{\lambda} = R \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \] where: - \( R \) is the Rydberg constant, approximately \( 1.097 \times 10^7 \, \text{m}^{-1} \) or \( 10.97 \times 10^6 \, \text{m}^{-1} \). - \( n_1 \) is the lower energy level (for Balmer series, \( n_1 = 2 \)). - \( n_2 \) is the higher energy level (for Balmer series, \( n_2 = 3, 4, 5, ... \) up to infinity). 3. **Calculating the Wavelength for the First Line (n2 = 3)**: - Set \( n_1 = 2 \) and \( n_2 = 3 \): \[ \frac{1}{\lambda} = R \left( \frac{1}{2^2} - \frac{1}{3^2} \right) \] - Substitute the values: \[ \frac{1}{\lambda} = 10.97 \times 10^6 \left( \frac{1}{4} - \frac{1}{9} \right) \] - Calculate \( \frac{1}{4} - \frac{1}{9} \): \[ \frac{1}{4} - \frac{1}{9} = \frac{9 - 4}{36} = \frac{5}{36} \] - Now substitute back: \[ \frac{1}{\lambda} = 10.97 \times 10^6 \times \frac{5}{36} \] - Calculate \( \lambda \): \[ \lambda = \frac{36}{10.97 \times 10^6 \times 5} \approx 6563 \, \text{Å} \] 4. **Calculating the Wavelength for the Last Line (n2 = ∞)**: - Set \( n_1 = 2 \) and \( n_2 = \infty \): \[ \frac{1}{\lambda} = R \left( \frac{1}{2^2} - 0 \right) \] - Substitute the values: \[ \frac{1}{\lambda} = 10.97 \times 10^6 \times \frac{1}{4} \] - Calculate \( \lambda \): \[ \lambda = \frac{4}{10.97 \times 10^6} \approx 3647 \, \text{Å} \] 5. **Determining the Range**: - From the calculations, we find that the wavelengths in the Balmer series range from: \[ 3647 \, \text{Å} \text{ to } 6563 \, \text{Å} \] 6. **Selecting the Correct Option**: - The correct option that matches this range is option 3: **3647 Å to 6563 Å**. ### Final Answer: The lines in the Balmer series have their wavelengths lying between **3647 Å and 6563 Å**.
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AAKASH INSTITUTE ENGLISH-ATOMS-ASSIGNMENT SECTION A Objective (One option is correct )
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  4. The energy of hydrogen atom in its ground state is -13.6 eV , the ener...

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  5. In which transition of a hydrogen atom, photons of lowest frequency ar...

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  6. Total energy of an electron in the hydrogen atom in the ground state i...

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  7. Using Bohr's formula for energy quantization, the ionisation potenti...

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  8. Which of the following cannot be the value of ionisation energy for a ...

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  9. Name the spectral series of hydrogen atom, which be in infrared region...

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  10. The energies of three conservative energy levels L3,L2 and L1 of hydro...

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  11. if the wavelength of first member of Lyman series is lambda then calcu...

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  12. In Bohr's model of the hydrogen atom, the ratio between the period of ...

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  13. How many time does the electron go round the first bohr orbit of hydro...

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  14. If an electron in hydrogen atom jumps from third orbit to second orbit...

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  15. If radius of first orbit of hydrogen atom is 5.29 ** 10^(-11) m, the r...

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  17. Let F(1) be the frequency of second line of Lyman series and F(2) be t...

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