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In the following common emitter configur...

In the following common emitter configuration an n-p-n transistor with current gain `beta=100` is used. What is the output voltage of the amplifier ?

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Input current `I_("in")=(V_("in"))/(R_("in"))=(lmV)/(1 k Omega)=10^(-6)A`
`:' beta =(I_("out"))/(I_("in"))`
`:' I_("out") =beta.I_("in") =100xx10^(-6) A =10^(-4)A`
`:. V_("Out")=I_("out").R_("out")=(10^(-4)A)(100kOmega)=10V`
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