For a `CE` transistor amplifier, the audio signal voltage across the collector resistance of `2k Omega` is `2V`. Suppose the current amplification factor of the transistor is `100`. The value of `R_(B)` in series with `V_(BB)` supply of `2V`, if the `DC` base current has to be `10` times the signal current is.

Explanation

To solve the problem step by step, we will follow the given information and apply the relevant formulas.

### Step 1: Determine the signal current (Ic) in the collector
Given that the audio signal voltage across the collector resistance (Rc) is 2V and Rc is 2kΩ, we can calculate the collector current (Ic) using Ohm's law.

\[ I_c = \frac{V_{c}}{R_{c}} = \frac{2V}{2000Ω} = 0.001A = 1mA \]
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