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The communication satellites are parked ...

The communication satellites are parked at a height of (from surface of earth)

A

36 km

B

360 km

C

3600 km

D

36000 km

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The correct Answer is:
To determine the height at which communication satellites are parked above the surface of the Earth, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Geostationary Satellites**: Communication satellites are often geostationary, meaning they remain fixed relative to a point on the Earth's surface. This is achieved when the satellite's orbital period matches the Earth's rotational period, which is 24 hours. 2. **Use the Formula for Orbital Period**: The relationship between the orbital period (T) of a satellite and its radius (r) from the center of the Earth is given by: \[ T^2 = \frac{4\pi^2}{GM} r^3 \] where \( G \) is the universal gravitational constant and \( M \) is the mass of the Earth. 3. **Convert Time Period to Seconds**: Since the time period \( T \) is given in hours, convert it to seconds: \[ T = 24 \text{ hours} = 24 \times 60 \times 60 = 86400 \text{ seconds} \] 4. **Rearrange the Formula**: We need to express the radius \( r \) in terms of \( T \): \[ r^3 = \frac{GMT^2}{4\pi^2} \] 5. **Substitute Known Values**: - \( G = 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \) - \( M = 6 \times 10^{24} \, \text{kg} \) - \( T = 86400 \, \text{s} \) Plugging these values into the equation: \[ r^3 = \frac{(6.67 \times 10^{-11})(6 \times 10^{24})(86400^2)}{4\pi^2} \] 6. **Calculate \( r \)**: First, calculate \( T^2 \): \[ T^2 = 86400^2 = 7.46496 \times 10^9 \, \text{s}^2 \] Now substitute \( T^2 \) into the equation: \[ r^3 = \frac{(6.67 \times 10^{-11})(6 \times 10^{24})(7.46496 \times 10^9)}{4 \times (3.14)^2} \] After calculating the right-hand side, we find \( r \). 7. **Find the Height \( h \)**: The radius \( r \) is the distance from the center of the Earth to the satellite. To find the height \( h \) above the Earth's surface, subtract the Earth's radius \( R \) (approximately \( 6.4 \times 10^6 \, \text{m} \)): \[ h = r - R \] 8. **Final Calculation**: After performing the calculations, you will find that: \[ h \approx 36000 \, \text{km} \] ### Conclusion: The height at which communication satellites are parked above the surface of the Earth is approximately **36000 km**.
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