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हम एक सरल लोलक कस दोलन - काल ज्ञात करते ...

हम एक सरल लोलक कस दोलन - काल ज्ञात करते है । प्रयोग के क्रमिक मापनों में लिए गए पाठ्यांक हैं : 2.63 s, 2.56 s, 2.42 s, 2.71 s एवं 2.80 s । निरपेक्ष त्रुटि , सापेक्ष त्रुटि एवं प्रतिशत त्रुटि परिकलित कीजिए ।

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To solve the problem of calculating the absolute error, relative error, and percentage error for the given time measurements of a simple pendulum, we will follow these steps: ### Step 1: Calculate the Mean Time (Tm) First, we need to calculate the mean of the given time measurements. The measurements are: - T1 = 2.63 s - T2 = 2.56 s - T3 = 2.42 s - T4 = 2.71 s ...
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एक 5 kg द्रव्यमान वाली वस्तु पर 2s के लिये एक नियत बल कार्यरत होता है। यह वस्तु के वेग को 3m/s से बढा 7m/s कर देता है। लगाये गये बल की मात्रा ज्ञात करें

The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 s , 2.56 s , 2.42 s , 2.71 s , and 2.80 s . Find the average absolute error.

The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 s , 2.56 s , 2.42 s , 2.71 s , and 2.80 s . Find the average absolute error.

In successive measurement, the reading of the period of oscillation of a simple pendulum were found to be 2.63s, 2.56s, 2.71s and 2.80s in an experiment. Calculate (i) mean value of the period oscillation (ii) absolute errer in each measurement (iii) mean absolute error (iv) releative error (v) percentage error and (vi) express the result in proper form.

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