Check the dimensional correctness of the following relation.
Volume of a sphere =`4/3pi"(radius)"^2`

Explanation

To check the dimensional correctness of the relation for the volume of a sphere, we will compare the dimensions of both sides of the equation.

**Step 1: Identify the Left-Hand Side (LHS)**
The LHS of the equation is the volume of a sphere. The dimension of volume is given by:
\[ \text{Dimension of Volume} = L^3 \]
where \(L\) represents length.
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