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The area of a sheet of length 10.2 cm an...

The area of a sheet of length 10.2 cm and width 68 cm addressed upto proper number of significant figures is

A

`69.26 cm^2`

B

`69.4 cm^2`

C

`69 cm^2`

D

`70 cm^2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the area of a sheet with a length of 10.2 cm and a width of 68 cm, we will follow these steps: ### Step 1: Identify the formula for the area of a rectangle. The area \( A \) of a rectangle is calculated using the formula: \[ A = \text{length} \times \text{width} \] ### Step 2: Substitute the given values into the formula. Here, the length \( L = 10.2 \, \text{cm} \) and the width \( W = 68 \, \text{cm} \). Therefore, we substitute these values into the formula: \[ A = 10.2 \, \text{cm} \times 68 \, \text{cm} \] ### Step 3: Perform the multiplication. Now, we calculate the area: \[ A = 10.2 \times 68 = 693.6 \, \text{cm}^2 \] ### Step 4: Determine the number of significant figures. Next, we need to consider the significant figures in our measurements: - The length \( 10.2 \, \text{cm} \) has **3 significant figures**. - The width \( 68 \, \text{cm} \) has **2 significant figures**. The result should be reported with the least number of significant figures from the measurements used in the calculation, which is **2 significant figures**. ### Step 5: Round the result to the correct number of significant figures. The calculated area is \( 693.6 \, \text{cm}^2 \). To round this to 2 significant figures: - The first two digits are **69**. - The next digit (3) is less than 5, so we do not round up. Thus, the area rounded to 2 significant figures is: \[ A \approx 69 \, \text{cm}^2 \] ### Final Answer: The area of the sheet, addressed to the proper number of significant figures, is \( 69 \, \text{cm}^2 \). ---
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