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The amount of heat energy Q, used to hea...

The amount of heat energy Q, used to heat up a substance depends on its mass m its specific heat capacity (s) and the change in temperature `DeltaT` of the substance. Using dimensional method, find the expression for s is ( Given that `[S]=[L^2 T^(-2)K^(-1)]`) is

A

`QmDeltaT`

B

`Q/(mDeltaT)`

C

`"Qm"/(DeltaT)`

D

`m/(QDeltaT)`

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The correct Answer is:
To find the expression for specific heat capacity \( s \) using dimensional analysis, we start by recognizing that the amount of heat energy \( Q \) used to heat a substance depends on its mass \( m \), its specific heat capacity \( s \), and the change in temperature \( \Delta T \). ### Step-by-Step Solution: 1. **Identify the relationship**: We can express the relationship as: \[ Q = k \cdot m^b \cdot (\Delta T)^c \] where \( k \) is a dimensionless constant, and \( a \), \( b \), and \( c \) are the powers we need to determine. 2. **Write down the dimensions**: - The dimension of heat energy \( Q \) is given by: \[ [Q] = [M][L^2][T^{-2}] \] - The dimension of mass \( m \) is: \[ [m] = [M] \] - The dimension of change in temperature \( \Delta T \) is given as: \[ [\Delta T] = [K] \] - The dimension of specific heat capacity \( s \) is given as: \[ [s] = [L^2][T^{-2}][K^{-1}] \] 3. **Set up the dimensional equation**: We can equate the dimensions from both sides: \[ [s] = [Q]^{a} [m]^{b} [\Delta T]^{c} \] Substituting the dimensions: \[ [L^2][T^{-2}][K^{-1}] = ([M][L^2][T^{-2}])^{a} \cdot ([M])^{b} \cdot ([K])^{c} \] 4. **Expand the right-hand side**: This gives us: \[ [L^2][T^{-2}][K^{-1}] = [M^{a+b}][L^{2a}][T^{-2a}][K^{c}] \] 5. **Equate the dimensions**: Now we can equate the powers of each dimension: - For mass \( M \): \[ a + b = 0 \quad \text{(1)} \] - For length \( L \): \[ 2a = 2 \quad \text{(2)} \] - For time \( T \): \[ -2a = -2 \quad \text{(3)} \] - For temperature \( K \): \[ c = -1 \quad \text{(4)} \] 6. **Solve the equations**: From equation (2): \[ a = 1 \] Substitute \( a = 1 \) into equation (1): \[ 1 + b = 0 \implies b = -1 \] From equation (4): \[ c = -1 \] 7. **Write the expression for specific heat capacity**: Now substituting \( a \), \( b \), and \( c \) back into the relationship: \[ s = k \cdot Q^{1} \cdot m^{-1} \cdot (\Delta T)^{-1} \] Assuming \( k = 1 \): \[ s = \frac{Q}{m \cdot \Delta T} \] ### Final Expression: Thus, the expression for specific heat capacity \( s \) is: \[ s = \frac{Q}{m \cdot \Delta T} \]
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