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Frequency is the function of density (rh...

Frequency is the function of density `(rho)` , length `(a)` and surface tension `(T)` . Then its value is

A

`krho^(1//2) l^(3//2) T^(-1//2)`

B

`krho^(3//2) l^(3//2) T^(-1//2)`

C

`krho^(1//2) l^(3//2) T^(-3//4)`

D

`kT^(1//2) rho^(-1//2) l^(-3//2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the relationship for frequency (f) as a function of density (ρ), length (a), and surface tension (T), we can use dimensional analysis. Here’s a step-by-step solution: ### Step 1: Define the relationship Assume that frequency (f) can be expressed as: \[ f = K \cdot \rho^A \cdot a^B \cdot T^C \] where \( K \) is a dimensionless constant, and \( A \), \( B \), and \( C \) are the powers we need to determine. ### Step 2: Write down the dimensions The dimensions of frequency (f) are: \[ [f] = T^{-1} \] Now, we will write the dimensions of each variable: - Density (ρ): \[ [\rho] = \frac{M}{L^3} = M L^{-3} \] - Length (a): \[ [a] = L \] - Surface tension (T): \[ [T] = \frac{F}{L} = \frac{M L T^{-2}}{L} = M T^{-2} \] ### Step 3: Substitute dimensions into the equation Substituting the dimensions into the equation gives: \[ T^{-1} = (M L^{-3})^A \cdot (L)^B \cdot (M T^{-2})^C \] ### Step 4: Expand the right-hand side This expands to: \[ T^{-1} = M^{A+C} \cdot L^{-3A + B} \cdot T^{-2C} \] ### Step 5: Equate the dimensions Now we equate the dimensions on both sides: 1. For mass (M): \[ A + C = 0 \] 2. For length (L): \[ -3A + B = 0 \] 3. For time (T): \[ -2C = -1 \] ### Step 6: Solve the equations From the third equation: \[ -2C = -1 \implies C = \frac{1}{2} \] Substituting \( C \) into the first equation: \[ A + \frac{1}{2} = 0 \implies A = -\frac{1}{2} \] Now substituting \( A \) into the second equation: \[ -3(-\frac{1}{2}) + B = 0 \implies \frac{3}{2} + B = 0 \implies B = -\frac{3}{2} \] ### Step 7: Write the final expression Now we can substitute the values of \( A \), \( B \), and \( C \) back into the original equation: \[ f = K \cdot \rho^{-\frac{1}{2}} \cdot a^{-\frac{3}{2}} \cdot T^{\frac{1}{2}} \] ### Step 8: Simplify the expression This can be rewritten as: \[ f = K \cdot \frac{T^{\frac{1}{2}}}{\rho^{\frac{1}{2}} \cdot a^{\frac{3}{2}}} \] ### Conclusion Thus, the frequency is given by: \[ f \propto \frac{T^{\frac{1}{2}}}{\rho^{\frac{1}{2}} \cdot a^{\frac{3}{2}}} \]
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