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Let y=A sin (omegat-kx) represent the v...

Let `y=A sin (omegat-kx)` represent the variation of distance y of a particle with time t. Which of the following is not meaningful?

A

`y/A+omega`

B

`y/omega+"At"/"kx"`

C

A-kx

D

`A+omega/k`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given options is not meaningful in the context of the expression \( y = A \sin(\omega t - kx) \), we need to analyze the dimensions of each option provided. ### Step-by-Step Solution: 1. **Understanding the Expression**: The expression \( y = A \sin(\omega t - kx) \) describes a wave, where: - \( y \) is the displacement (dimension of length, \( [L] \)). - \( A \) is the amplitude (also dimension of length, \( [L] \)). - \( \omega \) is the angular frequency (dimension \( [T^{-1}] \)). - \( k \) is the wave number (dimension \( [L^{-1}] \)). - \( t \) is time (dimension \( [T] \)). - \( x \) is position (dimension \( [L] \)). 2. **Analyzing the Dimensions**: The term \( \omega t \) has dimensions: \[ [\omega t] = [T^{-1}][T] = [1] \text{ (dimensionless)} \] The term \( kx \) has dimensions: \[ [kx] = [L^{-1}][L] = [1] \text{ (dimensionless)} \] Since both \( \omega t \) and \( kx \) are dimensionless, their difference \( \omega t - kx \) is also dimensionless, making the sine function valid. 3. **Evaluating Each Option**: - **Option A**: \( \frac{y}{A} + \omega \) - Dimensions: \( \frac{[L]}{[L]} + [T^{-1}] = [1] + [T^{-1}] \) - This is not meaningful as you cannot add a dimensionless quantity to a quantity with dimension \( [T^{-1}] \). - **Option B**: \( \frac{y}{\omega} + \frac{At}{kx} \) - Dimensions: \( \frac{[L]}{[T^{-1}]} + \frac{[L][T]}{[L^{-1}][L]} = [L][T] + [T] = [L][T] + [T] \) - This is meaningful since both terms can be combined. - **Option C**: \( A - kx \) - Dimensions: \( [L] - [1] = [L] - [1] \) - This is not meaningful as you cannot subtract a dimensionless quantity from a quantity with dimension \( [L] \). - **Option D**: \( A + \frac{\omega}{k} \) - Dimensions: \( [L] + \frac{[T^{-1}]}{[L^{-1}]} = [L] + [L][T^{-1}] \) - This is not meaningful since you cannot add quantities with different dimensions. 4. **Conclusion**: The options that are not meaningful are A, C, and D. However, since the question asks for which is not meaningful among the provided options, we can conclude that: - **Option A** is the first option that is clearly not meaningful. ### Final Answer: **Option A** is not meaningful.
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