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Suppose two students trying to make a ne...

Suppose two students trying to make a new measurement system so that they can use it like a code measurement system and others do not understand it Instead of taking 1 kg, 1 m and 1 second, as basic unit they took unit of mass as `alpha` kg, the unit of length as `beta` m and unit of times as `gamma` second. They called power in new system as "Aakash", then find The value of `alpha` "Aakash" in watt.

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To solve the problem, we need to find the value of "Aakash" in watts, given the new measurement system defined by the students. Let's break it down step by step. ### Step 1: Understand the Definition of Power Power is defined as the work done per unit time. Mathematically, it can be expressed as: \[ P = \frac{W}{t} \] where \(P\) is power, \(W\) is work done, and \(t\) is time. ### Step 2: Express Work in Terms of Force and Displacement Work can be expressed as the product of force and displacement: \[ W = F \cdot x \] where \(F\) is force and \(x\) is displacement. ### Step 3: Express Force in Terms of Mass and Acceleration Force can be defined using Newton's second law: \[ F = m \cdot a \] where \(m\) is mass and \(a\) is acceleration. ### Step 4: Substitute Force into the Work Equation Substituting the expression for force into the work equation gives: \[ W = (m \cdot a) \cdot x \] ### Step 5: Substitute Acceleration and Displacement Acceleration can be expressed as \(a = \frac{F}{m}\) or in terms of units as \(m/s^2\). Thus, we can write: \[ W = m \cdot \left(\frac{x}{t^2}\right) \cdot x \] This leads to: \[ W = m \cdot x^2 / t^2 \] ### Step 6: Substitute Work into the Power Equation Now substituting the expression for work back into the power equation: \[ P = \frac{m \cdot x^2}{t^2} \cdot \frac{1}{t} = \frac{m \cdot x^2}{t^3} \] ### Step 7: Substitute the Units In the new measurement system: - Mass \(m\) is represented as \(\alpha\) kg - Length \(x\) is represented as \(\beta\) m - Time \(t\) is represented as \(\gamma\) seconds Substituting these into the power equation gives: \[ P = \frac{\alpha \cdot \beta^2}{\gamma^3} \] ### Step 8: Define "Aakash" In the new system, they have defined power as "Aakash". Therefore: \[ \text{Aakash} = \frac{\alpha \cdot \beta^2}{\gamma^3} \] ### Step 9: Express Aakash in Terms of Watts Since 1 watt (W) is defined as \(1 \text{ kg} \cdot \text{m}^2/\text{s}^3\), we can express the relationship: \[ \text{Aakash} = \alpha \cdot \beta^2 \cdot \gamma^{-3} \] ### Final Expression Thus, the value of "Aakash" in watts is: \[ \text{Aakash} = \alpha \cdot \beta^2 \cdot \gamma^{-3} \] ### Summary The final answer is: \[ \text{Aakash} = \alpha \cdot \beta^2 \cdot \gamma^{-3} \text{ (in watts)} \]
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