Home
Class 12
MATHS
Two adjacent sides of a parallelogram ar...

Two adjacent sides of a parallelogram are `4x+5y=0`,and `7x+2y=0`. If the equation of one diagonal is `11x+7y=9`
Area of the parallelogram is

A

`(0,0)`

B

`(1,1)`

C

`((5)/(3),(4)/(3))`

D

All of these

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-E (ASSERTION-REASON TYPE QUESTIONS)|6 Videos

  • STRAIGHT LINES

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-F (MATRIX-MATHC TYPE QUESTION)|3 Videos

  • STRAIGHT LINES

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION C) (OBJECTIVE TYPE QUESTIONS) (MORE THAN ONE ANSWER)|14 Videos

  • STATISTICS

    AAKASH INSTITUTE ENGLISH|Exercise Section-C Assertion-Reason|15 Videos

  • THREE DIMENSIONAL GEOMETRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - J|10 Videos

Similar Questions

Explore conceptually related problems

Two consecutive sides of a parallelogram are 4x+5y=0 and 7x+2y=0 . If the equation of one diagonal is 11 x=7y=9, find the equation of the other diagonal.

Two consecutive sides of a parallelogram are 4x+5y=0 and 7x+2y=0 . If the equation of one diagonal is 11 x+7y=9, find the equation of the other diagonal.

Two consecutive sides of a parallelogram are 4x+5y=0 and 7x+2y=0. If the equation of one diagonal is 11 x+7y=9, Equation of other diagonal : (A) 11x + 7y =0 (B) 3x - 5y + 5 = 0 (C) 7x + 11y = 0 (D) x-y =0

The two adjacent sides of parallelogram are y = 0 and y=sqrt3(x-1) . If equation of one diagonal is sqrt3y=(x+1) , then equation of other diagonal is

If the lines represented by 2x^2-5xy+2y^2=0 be the sides of a parallelogram and the line 5x+2y=1 be one of its diagonal. Find the equation of the other diagonal, and area of the parallelogram .

ABCD is a parallelogram. x + 2y = 3 and 2x + y = 3 are the equations of the diagonals AC and BD respectively. AC = 4 units and area of parallelogram ABCD is 8 sq. units then The length of BC is equal to

The equation to a pair of opposite sides of a parallelogram are x^2-5x+6=0 and y^2-6y+5=0 . The equations to its diagonals are x+4y=13 ,y=4x-7 (b) 4x+y=13 ,4y=x-7 4x+y=13 ,y=4x-7 (d) y-4x=13 ,y+4x-7

The equation to a pair of opposite sides of a parallelogram are x^2-5x+6=0 and y^2-6y+5=0 . The equations to its diagonals are x+4y=13 ,y=4x-7 (b) 4x+y=13 ,4y=x-7 4x+y=13 ,y=4x-7 (d) y-4x=13 ,y+4x-7

The point (-4,5) is vertex of a square and one of its diagonal is 7x-y+8=0. The equation of other diagonal is

Two sides of a parallelogram are along the lines x+y=3 and x=y+3. If its diagonals intersect at (2, 4) , then one of its vertices is