Home
Class 12
MATHS
The equations of two equal sides A Ba n ...

The equations of two equal sides `A Ba n dA C` of an isosceles triangle `A B C` are `x+y=5` and `7x-y=3` , respectively. Then the equation of side `B C` if `a r( A B C)=5u n i t^2` is `x-3y+1=0` (b) `x-3y-21=0` `3x+y+2=0` (d) `3x+y-12=0`

A

`x-3y+1=0`

B

`x-3y+21=0`

C

`3x+y-2=0`

D

`3x+y-12=0`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-I (SUBJECTIVE TYPE QUESTIONS)|5 Videos

  • STATISTICS

    AAKASH INSTITUTE ENGLISH|Exercise Section-C Assertion-Reason|15 Videos

  • THREE DIMENSIONAL GEOMETRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - J|10 Videos

Similar Questions

Explore conceptually related problems

The equations of the sides A B ,\ B C\ a n d\ C A\ of\ "triangle"A B C\ a r e\ y-x=2,\ x+2y=1\ a n d\ 3x+y+5=0 respectively. The equation of the altitude through B is x-3y+1=0 b. x-3y+4=0 c. 3x-y+2=0 d. none of these

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

Three sides A B ,A Ca n dC A of triangle A B C are 5x-3y+2=0,x-3y-2=0a n dx+y-6=0 respectively. Find the equation of the altitude through the vertex Adot

The sides A Ba n dA C of a triangle A B C are respectively 2x+3y=29a n dx+2y=16 respectively. If the mid-point of B Ci s(5,6) then find the equation of B Cdot

The equations of two sides of a triangle are 3x-2y+6=0\ a n d\ 4x+5y-20\ a n d\ the orthocentre is (1,1). Find the equation of the third side.

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot

Find the equation of the sides of a triangle having B (-4, -5) as a vertex, 5x+3y-4=0 and 3x+8y+13=0 as the equations of two of its altitudes.

If the equations of three sides of a triangle are x+y=1, 3x + 5y = 2 and x - y = 0 then the orthocentre of the triangle lies on the line/lines

In triangle A B C , the equation of side B C is x-y=0. The circumcenter and orthocentre of triangle are (2, 3) and (5, 8), respectively. The equation of the circumcirle of the triangle is a) x^2+y^2-4x+6y-27=0 b) x^2+y^2-4x-6y-27=0 c) x^2+y^2+4x-6y-27=0 d) x^2+y^2+4x+6y-27=0