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Find the position vector of centroid of a triangle having position vector of its vertices as `2i+3j-4k, -2i+3j+4k and -6j

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The position vector of centroid `=(veca+vecb+vecc)/(3)`
`=((2hati+3hatj-4hatk)+(-2hati+3hatj+4hatk)+(-6hatj))/(3)=vec0`(Null vector)
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