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For any two vectors vecp and vecq, show ...

For any two vectors `vecp` and `vecq`, show that `|vecp.vecq| le|vecp||vecq|`.

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To prove that \(|\vec{p} \cdot \vec{q}| \leq |\vec{p}| |\vec{q}|\), we will use the properties of the dot product and the cosine of the angle between the two vectors. ### Step-by-Step Solution: 1. **Define the Vectors**: Let \(\vec{p} = x \hat{i} + y \hat{j} + z \hat{k}\) and \(\vec{q} = a \hat{i} + b \hat{j} + c \hat{k}\). 2. **Calculate the Dot Product**: ...
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