Home
Class 12
MATHS
VECTOR ALGEBRA | LINEAR COMBINATION LINE...

VECTOR ALGEBRA | LINEAR COMBINATION LINEAR INDEPENDENCE AND LINEAR DEPENDENCE | Definition and physical interpretation: Linear Combination, Linear Combination: Linear Independence And Linear Dependence, Linearly Independent, Linearly Dependent, Theorem 1: If `veca` and `vecb` are two non collinear vectors; then every vector `vecr` coplanar with `veca` and `vecb` can be expressed in one and only one way as a linear combination: x`veca`+y`vecb`., Theorem 2: If `veca`, `vecb` and `vecc` are non coplanar vectors; then any vector `vecr` can be expressed as linear combination: x`veca`+y`vecb`+z`vecc`, Theorem 3:If vectors `veca`, `vecb` and `vecc` are coplanar then det(`veca` `vecb` `vecc`) = 0, Examples: Prove that the segment joining the middle points of two non parallel sides of a trapezium is parallel to the parallel sides and half of their sum., Components of a vector in terms of coordinates of its end points

Text Solution

AI Generated Solution

To prove that the segment joining the midpoints of two non-parallel sides of a trapezium is parallel to the parallel sides and half of their sum, we can follow these steps: ### Step 1: Define the trapezium and its points Let the trapezium be \( ABCD \) where \( AB \) and \( CD \) are the parallel sides, and \( AD \) and \( BC \) are the non-parallel sides. Let \( M \) and \( N \) be the midpoints of sides \( AD \) and \( BC \) respectively. ### Step 2: Use the midpoint theorem According to the midpoint theorem, the line segment joining the midpoints of two sides of a triangle is parallel to the third side and half as long. In our case, we will apply this theorem to triangles \( ABD \) and \( BCD \). ...
Promotional Banner

Topper's Solved these Questions

  • VECTOR ALGEBRA

    AAKASH INSTITUTE ENGLISH|Exercise ILLUSTRATION|1 Videos
  • VECTOR ALGEBRA

    AAKASH INSTITUTE ENGLISH|Exercise TRY YOURSELF|20 Videos
  • TRIGNOMETRIC FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise Section - J (Akash Challengers Question)|16 Videos

Similar Questions

Explore conceptually related problems

If a and b are two non collinear vectors; then every vector r coplanar with a and b can be expressed in one and only one way as a linear combination: xa+yb=0.

If veca and vecb are othogonal unit vectors, then for a vector vecr non - coplanar with veca and vecb vector vecr xx veca is equal to

If veca and vecb are two non collinear vectors and vecu = veca-(veca.vecb).vecb and vecv=veca x vecb then vecv is

If veca, vecb, vecc are any three non coplanar vectors, then [(veca+vecb+vecc, veca-vecc, veca-vecb)] is equal to

If veca, vecb, vecc are any three non coplanar vectors, then (veca+vecb+vecc).(vecb+vecc)xx(vecc+veca)

If veca,vecb and vecc are non coplaner vectors such that vecbxxvecc=veca , veccxxveca=vecb and vecaxxvecb=vecc then |veca+vecb+vecc| =

If veca, vecb and vecc are three non-coplanar vectors, then (veca + vecb + vecc). [(veca + vecb) xx (veca + vecc)] equals

If veca, vecb, vecc are three non-coplanar vectors, then a vector vecr satisfying vecr.veca=vecr.vecb=vecr.vecc=1 , is

i. If veca, vecb and vecc are non-coplanar vectors, prove that vectors 3veca-7vecb-4vecc, 3veca-2vecb+vecc and veca+vecb+2vecc are coplanar.

If veca and vecb are non - zero vectors such that |veca + vecb| = |veca - 2vecb| then