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(CH(3))(2)C=CHCOCH(3) can be oxidised to...

`(CH_(3))_(2)C=CHCOCH_(3)` can be oxidised to `(CH_(3))_(2)C=CHCOOH` by

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Alkaline `KMnO_(4)` or `HNO_(3)` or `K_(2)Cr_(2)O_(7) // H^(+)` cannot be used for this purpose, because they all will result into oxidative cleavage at the double bond, Hence oxidation by NaOH + `I_(2)` (or NaOl) is the most suitable method for this conversion.
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Explore conceptually related problems

Suggest a suitable oxidising agent for the given conversion. (CH_(3))_(2)C = CH-COCH_(3) to (CH_(3))_(2) C= CHCOOH

CH_3 CH=CHCHO is oxidised to CH_3 CH=CHCOOH using :

Name the following compounds according to the IUPAC system of nomenclature: i. CH_(3)CH(CH_(3))CH_(2)CH_(2)CHO ii. CH_(3)CH_(2)COCH(C_(2)H_(5))CH_(2)CH_(2)Cl iii. CH_(3)CH=CHCHO iv. CH_(3)COCH_(2)COCH_(3) v. CH_(3)CH(CH_(3))CH_(2)C(CH_(3))_(2)COCH_(3) vi. (CH_(3))_(3)C CH_(2)COOH vii. OHC C_(6)H_(4)CHO-p

Write IUPAC names of the following compounds : (a) CH_(3)CH=C(CH_(3))_2 (b) CH_(2)=CH-C-=C-CH_(3) (c ) (d) (e ) {:(CH_(3)(CH_(2))_4CH(CH_(2))_3CH_(3)),(" "|),(" "CH_(2)-CH(CH_(3))_2):}

CH_(3)CH=CHCHO is oxidised to CH_(3)-CH=CHCOOH, using oxidising agent as :

Arrange the following in order of increasing acidic strength (i) HCOOH,ClCH_(2)COOH,CH_(3)COOH (ii) CH_(3)COOH,(CH_(3))_(2)CHCOOH,(CH_(3))_(3)CCOOH (iii) ClCH_(2)COOH,Cl_(2)CHCOOH,ClCl_(3)C.COOH (iv) ClCH_(2)COOH,CH_(3)CH_(2)COOH,ClCH_(2)CH_(2)COOH,(CH_(3))_(2)CH.COOH,CH_(3)COOH.

Arrange .the following in increasing order of stability of carbocation. (a) (CH_(3))_(2)C - CH_(2)CH_(3) (b) (CH_(3))_(3)C (c) (CH_(3))_(2) CH (d) CH_(3) CH_(2)

The systematic name of (CH_(3))_(2) CHCOOH is:

Arrange the following as stated : 'Increasing order of acidic strength'. ClCH_(2) COOH, CH_(3) CH_(2) COOH, ClCH_(2) CH_(2) COOH, (CH_(3))_(2) CHCOOH, CH_(3) COOH .

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