An ester 'A' `(C_(4)H_(8)O_(2))` on treatment with excess methyl magnesium chloride followed on acidification gives an alcohol 'B' as the sole organic product. Alochol 'B' as the organic product. Alcohol 'B' on oxidation with NaOCl followed by acidification gives acetic acid. Deduce structure of A and B. Show the reactions involved.

Explanation

To solve the problem step by step, we will deduce the structures of ester A and alcohol B based on the reactions described.

### Step 1: Identify the structure of ester A
Given that ester A has the formula \(C_4H_8O_2\), we can deduce its structure. The general formula for esters is \(RCOOR'\), where \(R\) and \(R'\) are hydrocarbon chains.

To satisfy the formula \(C_4H_8O_2\), one possible structure for ester A is:
- **Formate Ester**: \(HCOOCH_2CH_3\) (Ethyl formate)

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