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One of the rectangular components of a force of 40 N is 20 N. Find the angle it makes with the component.

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To solve the problem, we need to find the angle θ that the resultant force makes with one of its rectangular components. Here’s a step-by-step solution: ### Step 1: Understand the Components We have a resultant force (R) of 40 N and one of its rectangular components (H) which is given as 20 N. We will assume that the 20 N component is the horizontal component. ### Step 2: Use the Relationship Between Components The relationship between the resultant force and its horizontal component can be expressed using the cosine of the angle θ: \[ H = R \cdot \cos(\theta) \] Where: - \( H \) = horizontal component (20 N) - \( R \) = resultant force (40 N) - \( \theta \) = angle between the resultant and the horizontal component ### Step 3: Substitute the Known Values Substituting the known values into the equation: \[ 20 = 40 \cdot \cos(\theta) \] ### Step 4: Solve for Cosine To isolate \( \cos(\theta) \), divide both sides by 40: \[ \cos(\theta) = \frac{20}{40} \] \[ \cos(\theta) = \frac{1}{2} \] ### Step 5: Find the Angle Now, we need to find the angle \( \theta \) for which \( \cos(\theta) = \frac{1}{2} \). The angle that satisfies this condition is: \[ \theta = 60^\circ \] ### Final Answer Thus, the angle that the force makes with the horizontal component is: \[ \theta = 60^\circ \] ---
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