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A vector of magnitude 13 makes an angle ...

A vector of magnitude 13 makes an angle ` 65.37^(@)` with the x-axis . What is its component along positive y-axis ?

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To find the component of a vector along the positive y-axis, we can use the following steps: ### Step 1: Identify the given values - Magnitude of the vector (R) = 13 - Angle with the x-axis (θ) = 65.37° ### Step 2: Use the formula for the vertical component The vertical component (Vy) of the vector can be calculated using the formula: \[ Vy = R \cdot \sin(\theta) \] ### Step 3: Substitute the values into the formula Now, substituting the values we have: \[ Vy = 13 \cdot \sin(65.37°) \] ### Step 4: Calculate the sine of the angle Using a calculator or trigonometric tables, we find: \[ \sin(65.37°) \approx 0.91 \] ### Step 5: Calculate the vertical component Now, substituting the sine value back into the equation: \[ Vy = 13 \cdot 0.91 \] \[ Vy \approx 11.83 \] ### Final Answer The component of the vector along the positive y-axis is approximately **11.83**. ---
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