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The objects x and y are projected from a...

The objects x and y are projected from a point with same velocities , at angle `30 ^(@) and 60^(@) `, the ratio of their maximum height attained:

A

`1:1`

B

`1:3`

C

`1:2`

D

`4 :1 `

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The correct Answer is:
To find the ratio of the maximum heights attained by two objects projected at angles of \(30^\circ\) and \(60^\circ\) with the same initial velocity, we can follow these steps: ### Step 1: Write the formula for maximum height The maximum height \(H\) attained by a projectile is given by the formula: \[ H = \frac{u^2 \sin^2 \theta}{2g} \] where: - \(u\) is the initial velocity, - \(\theta\) is the angle of projection, - \(g\) is the acceleration due to gravity. ### Step 2: Define the maximum heights for both objects Let: - \(H_x\) be the maximum height for object X (projected at \(30^\circ\)), - \(H_y\) be the maximum height for object Y (projected at \(60^\circ\)). Using the formula: \[ H_x = \frac{u^2 \sin^2(30^\circ)}{2g} \] \[ H_y = \frac{u^2 \sin^2(60^\circ)}{2g} \] ### Step 3: Find the ratio of the maximum heights The ratio of the maximum heights \(H_x\) to \(H_y\) is: \[ \frac{H_x}{H_y} = \frac{\frac{u^2 \sin^2(30^\circ)}{2g}}{\frac{u^2 \sin^2(60^\circ)}{2g}} \] ### Step 4: Simplify the ratio Since \(u^2\) and \(2g\) are common in both the numerator and the denominator, they cancel out: \[ \frac{H_x}{H_y} = \frac{\sin^2(30^\circ)}{\sin^2(60^\circ)} \] ### Step 5: Calculate \(\sin^2(30^\circ)\) and \(\sin^2(60^\circ)\) We know: \[ \sin(30^\circ) = \frac{1}{2} \quad \Rightarrow \quad \sin^2(30^\circ) = \left(\frac{1}{2}\right)^2 = \frac{1}{4} \] \[ \sin(60^\circ) = \frac{\sqrt{3}}{2} \quad \Rightarrow \quad \sin^2(60^\circ) = \left(\frac{\sqrt{3}}{2}\right)^2 = \frac{3}{4} \] ### Step 6: Substitute the values into the ratio Now substituting these values into the ratio: \[ \frac{H_x}{H_y} = \frac{\frac{1}{4}}{\frac{3}{4}} = \frac{1}{3} \] ### Step 7: Conclusion Thus, the ratio of the maximum heights attained by objects X and Y is: \[ H_x : H_y = 1 : 3 \] ### Final Answer The ratio of the maximum height attained by objects X and Y is \(1 : 3\). ---
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