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A balloon starts rising from the earth's...

A balloon starts rising from the earth's surface. The ascension rate is constant and equal to `v_(0)`. Due to the wind. The balloon gathers the horizontal velocity component `v_(x)=ky`, where k is a constnat and y is the height of ascent. Find how the following quantities depednd on the height of ascent.
(a) the horizontal drift of the balloon x (y)
(b) the total tangential and normal accelrations of the balloon.

Text Solution

Verified by Experts

The correct Answer is:
(i) ` x = (ay^(2))/(2v_(0))` (ii) ` a_("total")=av_(0) a_("tangential")= (v_(0)a^(2)y)/(sqrt(v_(0)^(2) +a^(2)y^(2))),a_("normal")= (av_(0)^(2))/(sqrtv_(0)^(2)+a^(2)y^(2))`
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