A bar magnet is dropped through a horizontal aluminium ring along the axis of the ring. What will be direction of induced current in the loop for the observer shown? What will be the direction of magnetic force experienced by the bar magnet?

Explanation

As per Lenz's law, induced current in the loop will be such that it will oppose the cause of change in flux (that is motion of the bar magnet towards itself). Thus current flows in the loop so that it is equivalent to a bar magnet with its North facing the approaching North pole of the magnet, thereby repelling it. Thus current for the observer will be anticlockwise.

Thus, acceleration of the bar magnet a lt g.