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An angle aob made of a conducting wire ...

An angle aob made of a conducting wire moves along its bisector through a magnetic field B as suggested by figure. Find the emf induced between the two free ends if the magnetic field is perpendicular ot the plane of the angle.
(##HCV_VOL2_C38_S01_022_Q01##)
(##HCV_VOL2_C38_S01_022_Q02##)

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Verified by Experts

emf induced between ends B and C is
`V_(C)-V_(B)=Blvsin 60^(@)`
emf induced between end D and B is
`V_(B)-V_(D)=B/v sin 60^(@)`
So, `V_(A)-V_(B)=2xx(sqrt3)/(2)Blv=sqrt3Blv`
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