Two coils have self inductances `L_(1)=4 mH and L_(2)=8mH`. Current in both the coils is increasing at same rate. At an instant, when the power given to the two coils is same, find
(i) Ratio of current in the inductors.
(ii) Ratio of potential difference
(iii) Ratio of energy stored

Explanation

To solve the problem step by step, we will analyze the given information and use the relevant formulas for inductance, power, and energy stored in inductors.

### Given:
- Self-inductance of coil 1: \( L_1 = 4 \, \text{mH} = 4 \times 10^{-3} \, \text{H} \)
- Self-inductance of coil 2: \( L_2 = 8 \, \text{mH} = 8 \times 10^{-3} \, \text{H} \)
- The current in both coils is increasing at the same rate.
- The power given to both coils is the same.

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