The primary coil of an ideal transformer has 100 turns and the secondary coil has 600 turns. Then

Options

A. The power in the primary circuit is less than that in the secondary circuit
B. The current in two circuits are same
C. The voltage in the two circuits are same
D. The primary current is six times the secondary current

Answer

To solve the problem regarding the ideal transformer with a primary coil of 100 turns and a secondary coil of 600 turns, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values**:
- Number of turns in the primary coil (N1) = 100
- Number of turns in the secondary coil (N2) = 600

2. **Use the Transformer Turn Ratio**:
The relationship between the voltages and turns in an ideal transformer is given by:
\[ \frac{V_1}{V_2} = \frac{N_1}{N_2} \]
Substituting the values:
\[ \frac{V_1}{V_2} = \frac{100}{600} = \frac{1}{6} \]
This implies:
\[ V_2 = 6V_1 \]

3. **Use the Current Relationship**:
The relationship between the currents in the primary and secondary coils is given by:
\[ \frac{I_2}{I_1} = \frac{N_1}{N_2} \]
Substituting the values:
\[ \frac{I_2}{I_1} = \frac{100}{600} = \frac{1}{6} \]
This implies:
\[ I_1 = 6I_2 \]

4. **Power Relationship**:
For an ideal transformer, the power input to the primary coil is equal to the power output from the secondary coil:
\[ P_{primary} = P_{secondary} \]
This can be expressed as:
\[ V_1 I_1 = V_2 I_2 \]

5. **Check the Statements**:
- **Power in primary circuit is less than in secondary circuit**: This is incorrect because \(P_{primary} = P_{secondary}\).
- **Current in the two circuits are the same**: This is incorrect as \(I_1 = 6I_2\).
- **Voltage in the two circuits are the same**: This is incorrect as \(V_2 = 6V_1\).
- **Primary current is 6 times the secondary current**: This is correct since \(I_1 = 6I_2\).

### Conclusion:
The only correct statement is that the primary current is 6 times the secondary current.