Home
Class 12
PHYSICS
Two sources with intensity I(0) and 4I(0...

Two sources with intensity `I_(0)` and `4I_(0)` respectively, interfere at a point in a medium. Find the ratio of
(i) maximum and minimum possible intensities,
(ii) ratio of amplitudes

Text Solution

Verified by Experts

`I_(max)=(sqrt(l_(1))+sqrt(l_(2)))^(2)`
Here, `l_(1)=l_(0)` and `l_(2)=4I_(0)`
`:. I_(max)=(sqrt(l_(0))+sqrt(4l_(0)))^(2)=9I_(0)`
and `l_("min")=(sqrt(l_(1))-sqrt(l_(2)))^(2)`
`=l_(0)`
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    AAKASH INSTITUTE ENGLISH|Exercise Try yourself|24 Videos
  • WAVE OPTICS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-A (objective type question(one option is correct)))|55 Videos
  • UNITS AND MEASUREMENTS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - D)|15 Videos
  • WAVES

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT ( SECTION-D ( Assertion - Reason Type Questions ))|12 Videos

Similar Questions

Explore conceptually related problems

Two sources with intensity 4I_0 , and 9I_0 , interfere at a point in medium. The minimum intensity would be

Two sources with intensity 9 : 4 interfere in a medium. Then find the ratio of maximum to the minimum intensity in the interference pattern.

The ratio of intensities of two waves is 9:16. If these two waves interfere, then determine the ration of the maximum and minimum possible intensities.

If the ratio of amplitude of two waves is 4:3 , then the ratio of maximum and minimum intensity is

Ratio of amplitude for two wave is 1:4 .Find the ratio of maximum intensity to minimum intensity.

Ratio of amplitude for two wave is 1:3 .Find the ratio of maximum intensity to minimum intensity.

For an interference pattern, the maximum and minimum intensity ratio is 64 : 1 , then what will be the ratio of amplitudes ?

For an interference pattern, the maximum and minimum intensity ratio is 64 : 1 , then what will be the ratio of amplitudes ?

In the case of interference, the maximum and minimum intensities are in the ratio 16 : 9. Then

In YDSE ratio of width of slit is 4:1 , then ratio of maximum to minimum intensity