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A beam of light of wavelength 400 nm fal...

A beam of light of wavelength 400 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 2 m away from the slit. It is observed that 2nd order minima occurs at a distance of 2 mm from the position of central maxima. Find the width of the slit.

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Now point Q is the point of second order minima

Now `sin theta=tan theta~~theta=(2xx10^(-3))/2=10^(-3)`
Let the slit separation be a
Now for second order minima `theta=(2lambda)/a`
Equating `(2lambda)/a` by `theta=10^(-3)`, we obtain a =0.8 mm
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