In a single slit differaction pattern a monochromatic light of wavelength 500nm is used if angular position of the point where waves interfere from slit is `10^(-3)` radians from line of central maxima. If width of the slit is `500 mum`, then order of minima obtained on screen will be

Explanation

To solve the problem step by step, we will use the formula for the angular position of the minima in a single-slit diffraction pattern.

### Step 1: Identify the given values
- Wavelength of light, \( \lambda = 500 \, \text{nm} = 500 \times 10^{-9} \, \text{m} \)
- Angular position, \( \theta = 10^{-3} \, \text{radians} \)
- Width of the slit, \( a = 500 \, \mu\text{m} = 500 \times 10^{-6} \, \text{m} \)

### Step 2: Write down the formula for the angular position of minima
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