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(C(0))/(1)+(C(1))/(2)+(C(2))/(3)+ . . . ...

`(C_(0))/(1)+(C_(1))/(2)+(C_(2))/(3)+ . . . .+(C_(100))/(101)` equals

A

`(2^(101))/(101)`

B

`(2^(101)-1)/(101)`

C

`(3^(101))/(101)`

D

`(3^(101)-1)/(101)`

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The correct Answer is:
B
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