Statement-1:Sum of the coefficients of last 30 terms in the expansion of `(1+x)^(49)`. When expanded in ascending powers of x, is `2^(48)`.
Statement-2: `P^(th)` term from the end in the expansion of `(x+y)^(n)` is `(n-P+2)^(th)` term from the beginninig.

Answer

To solve the problem, we will analyze both statements provided in the question.

### Step 1: Analyze Statement 1
We need to find the sum of the coefficients of the last 30 terms in the expansion of \((1+x)^{49}\).

1. **Understanding the Expansion**:
The expansion of \((1+x)^{49}\) has \(n + 1 = 49 + 1 = 50\) terms, which are:
\[ \binom{49}{0}x^0, \binom{49}{1}x^1, \ldots, \binom{49}{49}x^{49} \]

2. **Sum of Coefficients**:
To find the sum of the coefficients of the entire expansion, we substitute \(x = 1\):
\[ (1 + 1)^{49} = 2^{49} \]

3. **Identifying Last 30 Terms**:
The last 30 terms in the expansion correspond to the terms from \(\binom{49}{20}x^{20}\) to \(\binom{49}{49}x^{49}\).

4. **Sum of Coefficients of Last 30 Terms**:
The sum of the coefficients of the last 30 terms can be expressed as:
\[ \sum_{k=20}^{49} \binom{49}{k} \]
This is equal to:
\[ \sum_{k=0}^{49} \binom{49}{k} - \sum_{k=0}^{19} \binom{49}{k} = 2^{49} - \sum_{k=0}^{19} \binom{49}{k} \]

5. **Using Symmetry**:
By the symmetry of binomial coefficients:
\[ \sum_{k=0}^{19} \binom{49}{k} = \sum_{k=30}^{49} \binom{49}{k} \]
Thus, the sum of the coefficients of the last 30 terms is:
\[ \sum_{k=20}^{49} \binom{49}{k} = 2^{49} - \sum_{k=0}^{19} \binom{49}{k} = 2^{49} - \sum_{k=30}^{49} \binom{49}{k} \]

6. **Conclusion for Statement 1**:
The sum of the coefficients of the last 30 terms is not equal to \(2^{48}\), therefore Statement 1 is **False**.

### Step 2: Analyze Statement 2
We need to verify if the \(P^{th}\) term from the end in the expansion of \((x+y)^{n}\) is the \((n-P+2)^{th}\) term from the beginning.

1. **Understanding the Terms**:
The \(P^{th}\) term from the end can be expressed as:
\[ T_{n-P+1} = \binom{n}{n-P} x^{n-P} y^{P} \]
The \(P^{th}\) term from the beginning is:
\[ T_{P} = \binom{n}{P-1} x^{n-(P-1)} y^{P-1} \]

2. **Identifying the Correspondence**:
The \(P^{th}\) term from the end corresponds to the \((n-P+1)^{th}\) term from the beginning, not \((n-P+2)^{th}\).

3. **Conclusion for Statement 2**:
Therefore, Statement 2 is also **False**.

### Final Conclusion
Both statements are incorrect. Thus, the correct option is that both statements are false.