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Find a(1) and a(9) if a(n) is given by ...

Find `a_(1) and a_(9)` if `a_(n)` is given by ` a_(n) = (n^(2))/(n+1)`

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Given .` a_(n) = (n^(2))/(n+1)`
Putting n = 7 and 9 , we get
`a_(7) = (49)/(8)`
`a_(9) = (81)/(10)`
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