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If a = 1 + "log"(x) yz, b = 1 + "log"(y)...

If `a = 1 + "log"_(x) yz, b = 1 + "log"_(y) zx, c =1 + "log"_(z) xy,` then ab+bc+ca =

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To solve the problem, we need to find the value of \( ab + bc + ca \) given: \[ a = 1 + \log_x (yz), \quad b = 1 + \log_y (zx), \quad c = 1 + \log_z (xy) \] ### Step 1: Rewrite \( a \), \( b \), and \( c \) ...
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