lf ` a_(n)={ {:(n^(2), "when n is odd"),(2n,"when n is even "):}`
then write down ten beginning from the fifth term .

Explanation

To find the ten terms starting from the fifth term of the sequence defined by \( a_n \), we will follow the rules given in the problem:

- \( a_n = n^2 \) when \( n \) is odd
- \( a_n = 2n \) when \( n \) is even

We need to calculate \( a_5 \) to \( a_{14} \) (which gives us ten terms starting from the fifth term).

### Step-by-step Solution:
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