Insert 5 numbers between 7 and 25 such that the resulting sequence is an A.P.

Explanation

Let ` A_(1) , A_(2), A_(3) , A_(4) , A_(5) ` be required A.M. s.
then ` A_(1) = a + (b-a)/(n+1) = 7 (25 -7)/(6)`
` = 7 + 3 = 10 `
` A_(2) = a+ 2 ((b - a)/(n+1)) = 13 `
` A_(3) = 16 `
` A_(4) = 19 `
` A_(5) = 22`
Hence five A.M.s between 7 and 25 are 10, 13, 16, 19 , and 22 .