Find the ` n^(th)` term of the G.P. `(3)/(2), (3)/(4), (3)/(8),….` also find its ` 20^(th)` term

Explanation

Here ` a= (3)/(2) , r = (1)/(2)`
` a_(n) = ar^(n-1) = (3)/(2) xx ((1)/(2))^(n-1) = (3)/(2^(n))`
` therefore a_(20) = (3)/(2^(10))` .