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The coefficient of x^(101) in the expan...

The coefficient of ` x^(101)` in the expansion of
` (1 - x) (1- 2x) (1 - 2^(2) x) - (1 - 2^(101) x)` is

A

`2^(4950) - 2^(5050)`

B

`2^(5051) - 2^(5152)`

C

`2^(4950) - 2^(5051)`

D

`2^(5050) - 2^(5152)`

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The correct Answer is:
To find the coefficient of \( x^{101} \) in the expansion of \[ (1 - x)(1 - 2x)(1 - 2^2 x) \cdots (1 - 2^{101} x) - (1 - 2^{101} x), \] we can follow these steps: ### Step 1: Define the function Let \[ f(x) = (1 - x)(1 - 2x)(1 - 2^2 x) \cdots (1 - 2^{101} x). \] ### Step 2: Understand the maximum power of \( x \) The maximum power of \( x \) in \( f(x) \) is \( x^{102} \) because there are 102 factors in the product (from \( 1 - 2^0 x \) to \( 1 - 2^{101} x \)). ### Step 3: Find the coefficient of \( x^{101} \) The coefficient of \( x^{101} \) in \( f(x) \) can be found by considering the contributions from choosing 101 terms from the 102 factors. This can be computed as: \[ \text{Coefficient of } x^{101} = -\sum_{i=0}^{101} 2^i, \] where \( i \) is the index of the term we are excluding. ### Step 4: Calculate the sum The sum \( \sum_{i=0}^{101} 2^i \) is a geometric series. The formula for the sum of a geometric series is: \[ S_n = a \frac{(r^n - 1)}{(r - 1)}, \] where \( a \) is the first term, \( r \) is the common ratio, and \( n \) is the number of terms. Here, \( a = 1 \), \( r = 2 \), and \( n = 102 \): \[ \sum_{i=0}^{101} 2^i = 1 \cdot \frac{(2^{102} - 1)}{(2 - 1)} = 2^{102} - 1. \] ### Step 5: Substitute back into the expression Thus, the coefficient of \( x^{101} \) in \( f(x) \) is: \[ -\sum_{i=0}^{101} 2^i = -(2^{102} - 1) = -2^{102} + 1. \] ### Step 6: Adjust for the subtraction of \( (1 - 2^{101} x) \) Now we need to consider the subtraction of \( (1 - 2^{101} x) \). The coefficient of \( x^{101} \) in \( (1 - 2^{101} x) \) is \( -2^{101} \). ### Step 7: Combine the results The final coefficient of \( x^{101} \) in the entire expression is: \[ (-2^{102} + 1) - (-2^{101}) = -2^{102} + 1 + 2^{101}. \] ### Step 8: Simplify the expression We can factor out \( -2^{101} \): \[ -2^{101}(2 - 1) + 1 = -2^{101} + 1. \] ### Final Answer Thus, the coefficient of \( x^{101} \) in the expansion is: \[ -2^{101} + 1. \]
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AAKASH INSTITUTE ENGLISH-SEQUENCES AND SERIES -Assignment (SECTION - B) One option is correct
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  19. sum(n=0)^(oo) (n^(2) + n + 1)/((n +1)!) is equal to

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