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Statement-1 : A function f : R rarr R sa...

Statement-1 : A function `f : R rarr R` satisfies the f(x) - f(y) = x-y, `AA x, y in R, f(0), f(1) gt 0`, then f(x) = x+1.
and
Statement-2 : If function `f : R rarr R` satisfied the above relationship then `f(1) + f(0) + f(3)` is equal to 7.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.

C

Statement -1 is False, Statement -2 is False

D

Statement -1 is False, Statement -2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze both statements step by step. ### Step 1: Analyze Statement 1 We are given that a function \( f: \mathbb{R} \to \mathbb{R} \) satisfies the equation: \[ f(x) - f(y) = x - y \quad \forall x, y \in \mathbb{R} \] This implies that the function \( f \) is linear. ### Step 2: Rearranging the Equation From the equation \( f(x) - f(y) = x - y \), we can rearrange it to express \( f(x) \): \[ f(x) = f(y) + (x - y) \] This indicates that the difference in the function values is equal to the difference in the input values. ### Step 3: Finding the Form of the Function Let’s assume \( f(x) = x + c \) for some constant \( c \). Then: \[ f(x) - f(y) = (x + c) - (y + c) = x - y \] This holds true for any constant \( c \). ### Step 4: Using Given Conditions We know from the problem statement that \( f(0) > 0 \) and \( f(1) > 0 \): - \( f(0) = 0 + c = c > 0 \) - \( f(1) = 1 + c > 0 \) From \( f(0) > 0 \), we conclude \( c > 0 \). ### Step 5: Specific Form of the Function If we take \( c = 1 \), then: \[ f(x) = x + 1 \] This satisfies both conditions \( f(0) = 1 > 0 \) and \( f(1) = 2 > 0 \). ### Conclusion for Statement 1 Thus, we can conclude that: \[ f(x) = x + 1 \] is indeed a solution that satisfies the conditions given in Statement 1. ### Step 6: Analyze Statement 2 Now we need to check Statement 2: \[ f(1) + f(0) + f(3) \] Calculating each term: - \( f(1) = 1 + 1 = 2 \) - \( f(0) = 0 + 1 = 1 \) - \( f(3) = 3 + 1 = 4 \) Adding these: \[ f(1) + f(0) + f(3) = 2 + 1 + 4 = 7 \] ### Conclusion for Statement 2 Thus, Statement 2 is also true. ### Final Conclusion Both statements are true, but Statement 2 is not a correct explanation for Statement 1 since it simply verifies a calculation based on the function derived from Statement 1. ### Summary - **Statement 1**: True (the function is \( f(x) = x + 1 \)) - **Statement 2**: True (but not a correct explanation for Statement 1)
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