Let `f : W-> W` be a given function satisfying `f(x) = f(x-1)+f(x-2)` for `x<=2`.If `f(0)=0 and f(1)=1` , ther find the value of `f(2) + f(3) + f(4) + f(5) + f(6)`.

Explanation

To solve the problem, we need to find the values of the function \( f(x) \) for \( x = 2, 3, 4, 5, 6 \) based on the given recurrence relation and initial conditions.

### Step-by-step Solution:

1. **Given Information**:
- The function \( f : W \to W \) satisfies the relation:
\[
f(x) = f(x-1) + f(x-2) \quad \text{for } x \geq 2
...