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Let f : {1, 2, 3} rarr {1, 2, 3] be a fu...

Let `f : {1, 2, 3} rarr {1, 2, 3]` be a function. Then the number of functions `g : {1, 2, 3} rarr {1, 2, 3}`. Such that f(x) = g(x) for atleast one `x in {1, 2, 3}` is

A

11

B

19

C

23

D

27

Text Solution

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The correct Answer is:
To solve the problem, we need to find the number of functions \( g: \{1, 2, 3\} \to \{1, 2, 3\} \) such that \( f(x) = g(x) \) for at least one \( x \in \{1, 2, 3\} \). ### Step-by-step Solution: 1. **Determine the Total Number of Functions**: - Each element in the domain \{1, 2, 3\} can map to any of the 3 elements in the codomain \{1, 2, 3\}. - Therefore, the total number of functions \( f \) from \{1, 2, 3\} to \{1, 2, 3\} is given by: \[ 3^3 = 27 \] - The same applies for the function \( g \). So, the total number of functions \( g \) is also: \[ 3^3 = 27 \] 2. **Calculate the Functions Where \( f(x) \neq g(x) \) for All \( x \)**: - To find the number of functions \( g \) such that \( f(x) \neq g(x) \) for all \( x \), we can consider the choices for \( g \). - For each \( x \) in \{1, 2, 3\}, \( g(x) \) must be different from \( f(x) \). Since \( f(x) \) has 1 fixed value, \( g(x) \) has 2 remaining choices. - Thus, the number of such functions \( g \) is: \[ 2 \times 2 \times 2 = 2^3 = 8 \] 3. **Calculate the Functions Where \( f(x) = g(x) \) for At Least One \( x \)**: - The total number of functions \( g \) is 27. The number of functions \( g \) such that \( f(x) \neq g(x) \) for all \( x \) is 8. - Therefore, the number of functions \( g \) such that \( f(x) = g(x) \) for at least one \( x \) is: \[ 27 - 8 = 19 \] ### Final Answer: Thus, the number of functions \( g \) such that \( f(x) = g(x) \) for at least one \( x \) is **19**.
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