There are 10 persons who are to seated around a circular table . Find the probability that two particular will always sit together .

Explanation

Here, 10 person are seated round table.
Total no. of ways in which 10 persons can sit along a round table = (10-1)!=9!
`therefore` Total no. of elementary events = 9!
Now if we regard two particular person as one person, then we will be left with only 9 persons. These 9 persons can be seated along a round table in (9-1)=8!
Also, those two particular persons can be arranged among themselves in 2! ways
`therefore` No. of favourable elementary events = `8!xx2!`
Thus, required probability `= (8!xx2!)/(9!)=2/9`