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If P(A) = 3/8, P(B) = 1/3 and P(AcapB)=1...

If P(A) = `3/8`, P(B) = `1/3` and `P(AcapB)=1/4` then `P(barAcapbarB)` equals

A

`5/12`

B

`7/12`

C

`13/24`

D

`17/24`

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The correct Answer is:
To find \( P(\bar{A} \cap \bar{B}) \), we can use the relationship between the union and intersection of events. Here are the steps: ### Step-by-Step Solution: 1. **Given Values**: - \( P(A) = \frac{3}{8} \) - \( P(B) = \frac{1}{3} \) - \( P(A \cap B) = \frac{1}{4} \) 2. **Find \( P(A \cup B) \)**: We use the formula: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] Substituting the given values: \[ P(A \cup B) = \frac{3}{8} + \frac{1}{3} - \frac{1}{4} \] 3. **Finding a Common Denominator**: The least common multiple of the denominators (8, 3, and 4) is 24. We convert each fraction: \[ P(A) = \frac{3}{8} = \frac{9}{24}, \quad P(B) = \frac{1}{3} = \frac{8}{24}, \quad P(A \cap B) = \frac{1}{4} = \frac{6}{24} \] 4. **Substituting into the Formula**: Now substitute these values back into the equation: \[ P(A \cup B) = \frac{9}{24} + \frac{8}{24} - \frac{6}{24} \] Simplifying this gives: \[ P(A \cup B) = \frac{9 + 8 - 6}{24} = \frac{11}{24} \] 5. **Finding \( P(\bar{A} \cap \bar{B}) \)**: We know that: \[ P(\bar{A} \cap \bar{B}) = 1 - P(A \cup B) \] Thus, \[ P(\bar{A} \cap \bar{B}) = 1 - \frac{11}{24} = \frac{24 - 11}{24} = \frac{13}{24} \] ### Final Answer: \[ P(\bar{A} \cap \bar{B}) = \frac{13}{24} \]
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