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If three distinct number are chosen randomly from the first 100 natural numbers, then the probability that all three of them are divisible by both 2 and 3 is `4//25` b. `4//35` c. `4//33` d. `4//1155`

A

`1/231`

B

`4/1155`

C

`1/55`

D

`1/5`

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The correct Answer is:
B
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